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6r^2+22r-84=0
a = 6; b = 22; c = -84;
Δ = b2-4ac
Δ = 222-4·6·(-84)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-50}{2*6}=\frac{-72}{12} =-6 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+50}{2*6}=\frac{28}{12} =2+1/3 $
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